compiling using g++

g++

asked 2014-03-06 05:34:24 -0600

Oded
31 ●2 ●3 ●6

updated 2014-03-07 04:25:31 -0600

Jomoos

979 ●6 ●21 ●29 http://www.tecnooc.com/

After installing gcc and gcc-c++ using yum, I tried to compile some extremely simple c++ programs, those of the kind that print "hello".

I used g++ -c prog.o prog.cpp and retrived the prog.o file without any problems
I used g++ -o prog.exe prog.o and retrived the prog.exe file without any problems

BUT, when i tried to run the program in the terminal by writing prog, I get

bash: prog: command not found...

does anyone knows why?? I've been trying to do that for some hours now...

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Can you run "ls -la prog.exe" ? Maybe the execution flag is not set.

keramidas ( 2014-03-09 13:06:17 -0600 )edit

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answered 2014-03-06 07:31:21 -0600

skytux

5792 ●23 ●71 ●122 http://gracca.github.io/

You should run prog.exe, not prog, because you called it prog.exe:

./prog.exe

HTH,

Germán.

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answered 2014-03-09 01:33:32 -0600

Oded
31 ●2 ●3 ●6

updated 2014-03-09 01:34:11 -0600

Of course i tried that too, neigher works. Did i have to write "./prog.exe"? Writing "prog.exe" is not enough? Thanks again

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So, apperantly Mr. skytux was partly right. It doesn't matter if i write "prog" or "prog.exe", but adding ./ before "prog" solved the problem. I realy wonder why... what does ./ means? i mean, i was in the right folder that contained the file prog.exe...

Oded ( 2014-03-09 17:03:00 -0600 )edit

Sounds like an execution flag is amiss... chmod +x prog.exe ...without which bash (or any other shell) tries to find 'prog' from the places told in $PATH variable.

"./" more or less stands for "within the current directory", and AFAIK implies execution whether executable flag is set or not.

daikane ( 2014-03-11 18:59:49 -0600 )edit

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compiling using g++

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